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Home/ Questions/Q 6037631
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T06:06:10+00:00 2026-05-23T06:06:10+00:00

Following code does compile in gcc 4.5 but it is not being compiled in

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Following code does compile in gcc 4.5 but it is not being compiled in visual c 2005.

int main()
{
    int len;
    len = 32;
    char buff[len];

    return 0;
}

I know that i am declaring array after statment, which is against ANSI C rules.

But why GCC does not give any error or warning, and in visual c, it gives error like,

error C2143: syntax error : missing ';' before 'type'

any ideas?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-23T06:06:10+00:00Added an answer on May 23, 2026 at 6:06 am

    Your C code is not C90 compliant. gcc -pedantic will warn about this.

    ~/tmp$ gcc -pedantic a.c
    a.c: In function ‘main’:
    a.c:5: warning: ISO C90 forbids variable length array ‘buff’
    a.c:5: warning: ISO C90 forbids mixed declarations and code
    ~/tmp$ 
    
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