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Editorial Team
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Asked: 2026-06-17T23:15:21+00:00

Following code #include <stdio.h> int main( int argc, char** argv ) { const char

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Following code 

#include <stdio.h>
int main( int argc, char** argv ) 
{
    const char *s = "";
    if (s == '\0') {
        int x = 0;
    }
    return 0;
}

It does not go in the loop. Why ? ,

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1 Answer

  1. Editorial Team

    Try

       if (*s == '\0') {
        int x = 0;
    }

    You want to compare the value of s, not it’s memory address.

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