Question

following code works properly

draw([['Rice',20,28,38],['Paddy',31,38,55],]);

but when i try using external variable like

var val1=20;
var val2=30;
var val3=40;
draw([['Rice',val1,val2,val3],['Paddy',31,38,55],]);

It wont work.

Answer 1

Just showing that your example code works fine using the Firebug console. Can you post more of your code? Your stripped-down example is probably missing something else that’s causing a problem.

What is your draw() function doing? Could something in that function be breaking?

EDIT: Another problem could be the trailing comma after your second array. That will throw an error in Internet Explorer.

alert([['Rice',val1,val2,val3],['Paddy',31,38,55],]);

should be:

alert([['Rice',val1,val2,val3],['Paddy',31,38,55]]);

That may solve your issue (though you also have that in your ‘working’ example, but I thought it worth mentioning).