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Home/ Questions/Q 7977589
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Editorial Team
  • 0
Editorial Team
Asked: June 4, 20262026-06-04T09:14:40+00:00 2026-06-04T09:14:40+00:00

Following is my code : function jsonpCallback(response){ //JSON.stringify(response) alert(response); } $.ajax({ url: url, dataType:

  • 0

Following is my code :

     function jsonpCallback(response){
                    //JSON.stringify(response)
                    alert(response);
                }                
                $.ajax({
                    url: url,
                    dataType: 'jsonp',
                    error: function(xhr, status, error) {
                        alert(error);
                    },
                    success: function(data) {
                        alert(data);
                        jsonpCallback(data);
                    }
                });

Here my url variable is the link which contain the following data and as per I know it is in the JSON format:

[{"destination":"United States","destinationId":"46EA10FA8E00","city":"LosAngeles","state":"California","country":"United States"}] etc..

I want to call jsonpCallback function after passing successive data to it. But success argument of $.ajax is not calling the function thats why I am not getting any data into it. But my debugger window showing response there, so why its not coming $.ajax function?

Any help…thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-04T09:14:42+00:00Added an answer on June 4, 2026 at 9:14 am

    Try to pass type of ajax call GET/POST.

    $.ajax({
         type: "GET",
         url: url,
         dataType: 'jsonp',
         error: function(xhr, status, error) { alert(error); },
         success: function(data) {
             alert(data);
             jsonpCallback(data);
         }
    });
    
     function jsonpCallback(response){
          //JSON.stringify(response)
          alert(response);
     }       
    
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