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Home/ Questions/Q 9174689
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T16:47:36+00:00 2026-06-17T16:47:36+00:00

Following is my code snippet: ApplicationContext ctx = new ClassPathXmlApplicationContext( classpath*:META-INF/spring/applicationContext*.xml); JpaTransactionManager jpatm =

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Following is my code snippet:

ApplicationContext ctx = new ClassPathXmlApplicationContext(
                    "classpath*:META-INF/spring/applicationContext*.xml");
            JpaTransactionManager jpatm = (JpaTransactionManager) ctx
                    .getBean("transactionManager");
            EntityManager em = jpatm.getEntityManagerFactory()
                    .createEntityManager();
String sqlQuery = "SELECT suc FROM SubUsrCont suc, UDMap uDMap WHERE suc.userid = uDMap.userid AND uDMap.parentuserid = :parentuserid";
TypedQuery<SubUsrCont> query = (TypedQuery<SubUsrCont>) em.createQuery(sqlQuery, SubUsrCont.class);
query.setParameter("parentuserid", parentid);
ArrayList<SubUsrCont> listContent = (ArrayList<SubUsrCont>) query.getResultList();

But when ever executed I get the following error:

[http-8080-1] ERROR org.hibernate.hql.PARSER - line 1:92: expecting OPEN, found '.'

Can anybody help???

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  1. Editorial Team
    Editorial Team
    2026-06-17T16:47:37+00:00Added an answer on June 17, 2026 at 4:47 pm

    Well, I found it and successfully tested it as well. It was due to my POJO package name. Previously it was in.myproject.myname. I changed it to com.myproject.myname. HQL was taking in as the SQL Keyword IN and was looking for OPEN ‘(‘.

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