Question

Following is my Php code where all country come from mysql database. It’s a user profile area where users can update their country name. But it’s not selected (html selected = selected) after he submit his country name.
May be it’s my $sel variable problem. Can some one fix it ?

<select name="country" class="country"> 
<?php
$sql=mysql_query("select * from country");
while($row=mysql_fetch_array($sql))
{
$id=$row['Code'];
$data=$row['Name'];

    if($data == $country2)
    {
        $sel = 'selected = "selected"';
    }
    else
    {
        $sel = "";
    }

echo '<option value="'.$id.'" $sel>'.$data.'</option>';
}
?>
</select>       

Answer 1

Variables are not parsed inside of single quotes. You use concatenation for the other variables in your statement, but not $sel…

echo '<option value="'.$id.'"' . $sel . '>'.$data.'</option>';

Or switch to double quotes..