Question

Following is my sql query in which i am trying to get the names of those people whose address is same but the problem i faced is that the query is showing the right count but all the names are not there grouped by and not in the following manner. Kindly let me know how can i modify the following query so i can get the address in a manner mentioned below and also count(address) = 1 should be ignored. Thanks,

+---------------------+
 Jhon  | Stree 9, H#4
 zame  | Stree 9, H#4
 sinn  | Stree 9, H#4
 linn  | Stree 8, H#9
 tinn  | Stree 8, H#9
+---------------------+

SELECT *,count(address) FROM `student` 
group by address
order by  count(address) desc

SQLFIDDLE: http://sqlfiddle.com/#!2/6d6ca/2

Answer 1

Try this:

 SELECT name, count(address) FROM student 
 GROUP BY address 
 ORDER BY count(address), name DESC

EDIT:
do you mean this group_concat ?

   SELECT GROUP_CONCAT(DISTINCT name ORDER BY name DESC SEPARATOR ' ')as name, 
    adress FROM student 
   GROUP BY adress 
  ORDER BY count(adress), name DESC

DEMO HERE