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Home/ Questions/Q 9234843
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T06:53:05+00:00 2026-06-18T06:53:05+00:00

Following is my try : – public void removeTail(){ Node precurrent=null; Node transverse=head; if(size

  • 0

Following is my try : –

public void removeTail(){
    Node precurrent=null;
    Node transverse=head;
    if(size != 0) {
        while(transverse.getNext() !=null) {
            System.out.println("oh"+transverse.getElement());
            precurrent=transverse;
            transverse=transverse.getNext();
        }
        precurrent.setNext(null);
        size--;
    }
    else{
        System.out.println("List is all ready empty");
    }
}

The problem with above code is that it gives error when there is only one node left and I try to remove it. This is because of the way I defined precurrent. Kindly suggest what should be done to handle this case. I don’t want to add the case of size==1.

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  1. Editorial Team
    Editorial Team
    2026-06-18T06:53:07+00:00Added an answer on June 18, 2026 at 6:53 am

    There are two possible ways.

    Either check if your size equals to 1.

    Or and this would be my solution, initialize precurrent with head just like you did it with transverse

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