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Home/ Questions/Q 6656289
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:37:29+00:00 2026-05-26T01:37:29+00:00

Following is the code that doesn’t work but it describes what I want to

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Following is the code that doesn’t work but it describes what I want to do.

Could you please recommend the best approach to this problem?

def resolveDriver(url: String) = {
  url match {
    case url.startsWith("jdbc:mysql:") => "com.mysql.jdbc.Driver"
    case url.startsWith("jdbc:postgresql:") => "org.postgresql.Driver"
    case url.startsWith("jdbc:h2:") => "org.h2.Driver"
    case url.startsWith("jdbc:hsqldb:") => "org.hsqldb.jdbcDriver"
    case _ => throw new IllegalArgumentException
  }
}
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  1. Editorial Team
    Editorial Team
    2026-05-26T01:37:30+00:00Added an answer on May 26, 2026 at 1:37 am

    In terms of syntax, you can modify just a tiny bit you case statements:

    case url if url.startsWith("jdbc:mysql:") => "com.mysql.jdbc.Driver"
    

    This simply binds the value url to the pattern expression (which is also url) and adds a guard expression with a test. That should make the code compile.

    To make it a little bit more scala-like, you can return an Option[String] (I removed a couple clause since it’s just for illustration):

    def resolveDriver(url: String) = url match {
      case u if u.startsWith("jdbc:mysql:") => Some("com.mysql.jdbc.Driver")
      case u if u.startsWith("jdbc:postgresql:") => Some("org.postgresql.Driver")
      case _ => None
    }
    

    That is unless you want to manage exceptions.

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