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Asked: 2026-06-12T13:09:25+00:00

Following on from a recent post. I am creating a search function that queries

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Following on from a recent post.

I am creating a search function that queries a SQL database. The database consists of different types of meat packaging. I have created HTML & PHP code that will search the database and display results using only one form and submit button. But I now want to create a search box that has multiple forms (including three dropdown ones), that when users type in sizes, click a dropdown and type in a id code, they can submit using one submit button and then will be referred to a page that consists of the results that match all three combined.

Can anyone give me some insight about how to go about this? I have tried creating two forms that submit to the same PHP page for results, but one seems to override the other.

Here is my HTML and PHP code currently: 

    <body>

    <form action="form2.php" method="post"> 
              Search: <input type="text" name="term" /><br />
    <input type="submit" value="Submit" /> 
    </form> 


</body>

And the PHP code:

   <body>


   <?php
    $con = mysql_connect ("localhost", "root", "");
    mysql_select_db ("delyn_db", $con);

  if (!$con)
    { 
    die ("Could not connect: " . mysql_error());
    }


$term = mysql_real_escape_string($_REQUEST['term']);    

     $sql = "SELECT * FROM delyn WHERE toolcode LIKE '%".$term."%' OR trayheight LIKE
     '%".$term."%' OR delyncode LIKE '%".$term."%' OR description LIKE '%".$term."%' 
      OR trayshape LIKE '%".$term."%' OR traydepth LIKE '%".$term."%' OR traywidth
     LIKE '%".$term."%'";
     $r_query = mysql_query($sql);

if(!$sql)
    {
        echo "could not find";
    }

       while ($row = mysql_fetch_array($r_query)){ 
       echo 'ID: ' .$row['ID']; 
       echo '<br /> Delyn code: ' .$row['delyncode']; 
       echo '<br /> Tool Code: '.$row['toolcode'];
       echo '<br /> Description: '.$row['description']; 
       echo '<br /> Tray range '.$row['trayrange']; 
       echo '<br /> Tray type: '.$row['traytype'];
       echo '<br /> Tray size: '.$row['traysize']; 
       echo '<br /> Tray height: '.$row['trayheight']; 
       echo '<br /> Tray width: '.$row['traywidth']; 
       echo '<br /> Tray depth: '.$row['traydepth'];
       echo '<br /> Tray shape: '.$row['trayshape'];  
       echo '<br /> imagename: '.$row['imagename'];
       echo '<br /> Tray live: '.$row['traylive'] . ' <br /><br />';  
    }


?>

    </body>

Thanks in advance 🙂

Edited php:

  <body>

    <?php
$con = mysql_connect ("localhost", "root", "");
mysql_select_db ("delyn_db", $con);

if (!$con)
    { 
    die ("Could not connect: " . mysql_error());
    }

if(isset($_POST['formSubmit']) )
{
    $varType = $_POST['traytype'];
}

$term = mysql_real_escape_string($_POST['term']);    
$sql = "SELECT * FROM delyn WHERE traytype LIKE '%".$varType."%'";


$r_query = mysql_query($sql);


while ($row = mysql_fetch_array($r_query)){ 
echo 'ID: ' .$row['ID']; 
echo '<br /> Delyn code: ' .$row['delyncode']; 
echo '<br /> Tool Code: '.$row['toolcode'];
echo '<br /> Description: '.$row['description']; 
echo '<br /> Tray range '.$row['trayrange']; 
echo '<br /> Tray type: '.$row['traytype'];
echo '<br /> Tray size: '.$row['traysize']; 
echo '<br /> Tray height: '.$row['trayheight']; 
echo '<br /> Tray width: '.$row['traywidth']; 
echo '<br /> Tray depth: '.$row['traydepth'];
echo '<br /> Tray shape: '.$row['trayshape'];  
echo '<br /> imagename: '.$row['imagename'];
echo '<br /> Tray live: '.$row['traylive'] . ' <br /><br />';  
    }


?>
  </body>
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1 Answer

  1. Editorial Team

    Why don’t you use multiple inputs on the same form? Something like this:

    <form action="form2.php" method="post"> 
          Search: <input type="text" name="term" /><br />
          Sizes: <input type="text" name="sizes" /><br />
          Select an option: <select name="dropdownselection" ><option...</option></select><br />
          ID Code: <input type="text" name="id" /><br />
<input type="submit" value="Submit" /> 
</form>

    Then you can access the values in the same way you accessed value entered for the search term.
    Note: you should use label tags for your labels, and use a list to layout your form.

    EDIT: An option tag looks like this:

    <option value="what is posted to the script">What is seen by the user</option>

    EDIT: Please remove the condition surrounding the $vartype variable assignment

    EDIT: Use and, not or, in your sql query, since you need both conditions to be true. If you have further questions, please open a new question, since this one is somewhat cluttered. Finally, if you feel this answer has helped you please consider accepting it.

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