Question

Following on this post, I have another problem – how can I combine two json data objects?

first json object,

{"file":{"name":"1024x768.jpg","type":"image\/jpeg","tmp_name":"C:\\wamp\\tmp\\php2C2E.tmp","error":0,"size":469159}}

second json object,

{"title":"title","content":"bla bla blah"}



$.post("process.php", first + second ,function(xml){

});

So I can get this array in process.php using print_r($_POST):

Array
(

[file] => Array
        (
            [name] => 1024x768.jpg
            [type] => image/jpeg
            [tmp_name] => C:\wamp\tmp\phpA1.tmp
            [error] => 0
            [size] => 469159
        )

    [title] => title
    [content] => bla bla blah
)

Answer 1

Looking at your first data object file is not an array as you are expecting it in the server side php code. It is a JSON object. Anyways you can try this to combine the data objects and post it.

var data1 = {"file":{"name":"1024x768.jpg","type":"image\/jpeg","tmp_name":"C:\\wamp\\tmp\\php2C2E.tmp","error":0,"size":469159}};
var data2 = {"title":"title","content":"bla bla blah"}

var data = data1;
data.title = data2.title;
data.content = data2.content;

$.post("process.php", data ,function(xml){

});

Alternatively you can use jQuery.extend method which merge the contents of two or more objects together into the first object.

var data1 = {"file":{"name":"1024x768.jpg","type":"image\/jpeg","tmp_name":"C:\\wamp\\tmp\\php2C2E.tmp","error":0,"size":469159}};
var data2 = {"title":"title","content":"bla bla blah"}

$.post("process.php", $.extend({}, data1, data2) ,function(xml){

});