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Home/ Questions/Q 68189
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Asked: May 10, 20262026-05-10T19:22:39+00:00 2026-05-10T19:22:39+00:00

Following techniques from ‘Modern C++ Design’, I am implementing a persistence library with various

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Following techniques from ‘Modern C++ Design’, I am implementing a persistence library with various compile-time optimisations. I would like the ability to dispatch a function to a templated member variable if that variable derives from a given class:

template<class T, template <class> class Manager = DefaultManager> class Data { private:    T *data_;  public:    void Dispatch()    {       if(SUPERSUBCLASS(Container, T))       {          data_->IKnowThisIsHere();       }       else       {          Manager<T>::SomeGenericFunction(data_);       }    } } 

Where SUPERSUBCLASS is a compile-time macro to determine object inheritance. Of course, this fails in all cases where T does to inherit from Container (or T is an intrinsic type etc etc) because the compiler rightly complains that IKnowThisIsHere() is not a data member, even though this code path will never be followed, as shown here after preprocessing with T = int:

private:    int *data_;  public:    void Dispatch()    {       if(false)       {          data_->IKnowThisIsHere(); 

Compiler clearly complains at this code, even though it will never get executed. A suggestion of using a dynamic_cast also does not work, as again a type conversion is attempted at compile time that is not possible (for example with T=double, std::string):

void Dispatch()    {       if(false)       {          dynamic_cast<Container*>(data_)->IKnowThisIsHere();  error: cannot dynamic_cast '((const Data<double, DefaultManager>*)this)->Data<double, DefaultManager>::data_' (of type 'double* const') to type 'class Container*' (source is not a pointer to class) error: cannot dynamic_cast '((const Data<std::string, DefaultManager>*)this)->Da<sttad::string, DefaultManager>::data_' (of type 'struct std::string* const') to type 'class Container*' (source type is not polymorphic) 

I really need to emulate (or indeed persuade!) having the compiler emit one set of code if T does inherit from Container, and another if it does not.

Any suggestions?

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  1. 2026-05-10T19:22:39+00:00Added an answer on May 10, 2026 at 7:22 pm

    Overloading can be useful to implement compile-time dispatching, as proposed by Alexandrescu in his book ‘Modern C++ Design’.

    You can use a class like this to transform at compile time a boolean or integer into a type:

    template <bool n> struct int2type { enum { value = n}; }; 

    The following source code shows a possible application:

    #include <iostream>  #define MACRO()   true  // <- macro used to dispatch   template <bool n> struct int2type { enum { value = n }; };  void method(int2type<false>) { std::cout << __PRETTY_FUNCTION__  << std::endl; }  void method(int2type<true>) { std::cout << __PRETTY_FUNCTION__  << std::endl; }  int main(int argc, char *argv[]) {     // MACRO() determines which function to call     //      method( int2type<MACRO()>());       return 0; } 

    Of course what really makes the job is the MACRO() or a better implementation as a metafunction

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