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Editorial Team
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Asked: 2026-06-12T19:56:57+00:00

Following this suggestion: How to convert ticks into a readable datetime with XSLT? which

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Following this suggestion: How to convert ticks into a readable datetime with XSLT? which shows how to convert Unix timestamp format in human readable datetime format, I wanted to convert Windows 64-bit filetime structure with XSL:

<xsl:value-of select="xs:dateTime('1960-01-01T00:00:00Z') + @WDT * xs:dayTimeDuration('PT0.0000001S')"/>

where @WDT attribute represents Windows 64-bit datetime number.

However I don’t get desired result. I get i.e. date: “2371-06-30T01:10:04.34375Z” for “129854922043437500”, while I expected: “30.06.2012 03:10:04”
What could be wrong in this approach?

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1 Answer

  1. Editorial Team

    The main problem is the initial dtae you are using — the correct date is January 1st 1601.

    So:

    <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:xs="http://www.w3.org/2001/XMLSchema">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="/">
   <xsl:value-of select=
   "xs:dateTime('1601-01-01T00:00:00Z')
     + 129854922043437500 idiv 10000000 *xs:dayTimeDuration('PT1S')"/>
 </xsl:template>
</xsl:stylesheet>

    when applied on any XML document (not used), produces exactly the wanted, correct result:

    2012-06-30T01:10:04Z
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