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Home/ Questions/Q 930897
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T20:24:48+00:00 2026-05-15T20:24:48+00:00

For a hw assignment, we are to code a reduce routine that looks like:

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For a hw assignment, we are to code a reduce routine that looks like:

int reduce(long array[], int size) 
//Where array is the array to reduce, and size is the size of the array.

Using STL. My initial thoughts were to create a set, put all items in the set with a comparison, but then I realized that the set I would create would never be usable since the function returns the size of the new set, but not the set itself to be used. So I’m not sure how I’d go about using the STL to reduce an array. Any thoughts? Thanks.

Edited:
Sorry, reduce is just to reduce the array into a sorted array without duplicates.

E.g. {4, 4, 2, 1} -> {1, 2, 4}
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  1. Editorial Team
    Editorial Team
    2026-05-15T20:24:49+00:00Added an answer on May 15, 2026 at 8:24 pm

    Sort the array using std::sort, then apply std::unique on it to remove duplicates. std::unique works only on sorted arrays. Just to simplify matters here is how you get begin and end of a native array:

    long* begin = array;
    long* end   = array + size;
    

    Once you have these two things, you can apply standard algorithms easily. Also, if you need to return the new size(used elements in the array):

    long* end_after_unique = unique(...);
    return end_after_unique - array;
    
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