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Home/ Questions/Q 7859901
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T22:04:24+00:00 2026-06-02T22:04:24+00:00

For a json object like this, list=[ {name:hello, category:verb}, {name:world, category:noun} ]; What would

  • 0

For a json object like this,

list=[
 {name:"hello",
  category:"verb"},
 {name:"world",
  category:"noun"}
];

What would be the fastest way to categorize the array using underscore to get this:

category=[
{id:"verb",
 list:[
  {name:"hello",
  category:"verb"}
 ]},
{id:"noun",
 list:[
  {name:"world",
  category:"noun"}
 ]}
];

It should be some kind of chained map-reduce… Of course I could do this easily using _.filter (but that would be slow), or using a for loop.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T22:04:26+00:00Added an answer on June 2, 2026 at 10:04 pm

    OK, I found it:

    groupBy _.groupBy(list, iterator)
    Splits a collection into sets, grouped by the result of running each value through iterator. If iterator is a string instead of a function, groups by the property named by iterator on each of the values.

    _.groupBy([1.3, 2.1, 2.4], function(num){ return Math.floor(num); });
    => {1: [1.3], 2: [2.1, 2.4]}
    
    _.groupBy(['one', 'two', 'three'], 'length');
    => {3: ["one", "two"], 5: ["three"]}
    

    So I did it using this(I already had a list):

    var listofwords=_.groupBy(doc.words, function(word){
            return word.category;
        });
        _.each(doc.lists,function(list){
            list.words=listofwords[list.name];
        });
    
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