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Home/ Questions/Q 8974473
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T18:41:23+00:00 2026-06-15T18:41:23+00:00

For containers such as std::map< std::string, std::unique_ptr< Foo >> , it looks like emplace()

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For containers such as std::map< std::string, std::unique_ptr< Foo >>, it looks like emplace() has yet to be implemented in stdc++ as of gcc 4.7.2.

Unfortunately, I can’t store Foo directly by value as it is an abstract super-class.

As a simple, but inefficient, place-holder, I’ve just been using std::map< std::string, Foo* > in conjunction with a std::vector< std::unique_ptr< Foo >> for garbage collection.

Do you have a interim solution that is more efficient and more easily replaced once emplace() is available?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T18:41:24+00:00Added an answer on June 15, 2026 at 6:41 pm

    What do you need emplace() for? Just move it in:

    #include <iostream>
    #include <map>
    #include <memory>
    #include <string>
    
    struct Foo
    {
        virtual ~Foo() = default;
    
        virtual std::string name() const = 0;
    };
    
    struct Bar : Foo
    {
        std::string name() const { return "Bar"; }
    };
    
    int main()
    {
        std::map<std::string, std::unique_ptr<Foo>> m;
    
        std::unique_ptr<Foo> p(new Bar());
        m.insert(std::make_pair("a", std::move(p)));
    
        std::cout << m["a"]->name() << std::endl;
    }
    

    In fact, you should not use emplace with unique_ptr‘s.

    As noted in my comment there, I now consider the use of new in user code an error. It should be replaced with make_unique, so you know your resource cannot possibly leak:

    // will be in std:: someday
    template <typename T, typename... Args>
    std::unique_ptr<T> make_unique(Args&&... args)
    {
        return std::unique_ptr<T>(new T(std::forward<Args>(args)...));
    }
    
    int main()
    {
        std::map<std::string, std::unique_ptr<Foo>> m;
    
        m.insert(std::make_pair("a", make_unique<Bar>()));
    
        std::cout << m["a"]->name() << std::endl;
    }
    
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