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Home/ Questions/Q 8504133
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T01:56:34+00:00 2026-06-11T01:56:34+00:00

For each identifier , how can I return the quantity when the received country

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For each identifier, how can I return the quantity when the received country is not equal to any of the delivered countries? I need an efficient query for the steps below since my table is huge.

These are the steps I would think could do this, of course you don’t need to follow them 🙂

  1. Create a group of ‘delivered’ countries for each identifier.
  2. See if ‘received’ is any of these countries for each identifier. If
    there is no match, return this result.

Starting Table:

identifier         delivered            received        quantity
-------------      ------------         -----------     ------------
1                  USA                  France          432
1                  France               USA             450
1                  Ireland              Russia          100
2                  Germany              Germany         1,034
3                  USA                  France          50
3                  USA                  USA             120

Result:

identifier         delivered            received        quantity
-------------      ------------         -----------     ------------
1                  Ireland              Russia          100 

The starting table is about 30,000,000 rows, so self-joins will be impossible unfortunately. I am using something similar to MySQL.

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  1. Editorial Team
    Editorial Team
    2026-06-11T01:56:36+00:00Added an answer on June 11, 2026 at 1:56 am

    I think LEFT JOIN query should work for you:

    SELECT a.*
    FROM starting a
         LEFT JOIN starting b
            ON a.id = b.id
               AND a.delivered = b.received
    WHERE b.received IS NULL;
    

    Example: SQLFiddle

    For optimizing above query, adding following composite index should give you better performance:

    ALTER TABLE starting  ADD KEY ix1(id, delivered, received);
    
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