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Asked: 2026-06-15T15:38:20+00:00

for example, a.boo method calls b.foo method. In b.foo method, how can I get

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for example, a.boo method calls b.foo method. In b.foo method, how can I get a’s file name (I don’t want to pass __file__ to b.foo method)…

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1 Answer

  1. Editorial Team

    You can use the inspect module to achieve this:

    frame = inspect.stack()[1]
module = inspect.getmodule(frame[0])
filename = module.__file__
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