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Home/ Questions/Q 335839
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T10:11:11+00:00 2026-05-12T10:11:11+00:00

For example, compare these two: function Person(name) { this.name = name; } var john

  • 0

For example, compare these two:

function Person(name) {
 this.name = name;
}
var john = new Person('John');
console.log(john.constructor);
// outputs: Person(name)

var MyJSLib = {
 Person : function (name) {
   this.name = name;
 }
}
var john2 = new MyJSLib.Person('John');
console.log(john2.constructor);
// outputs: function()

The first form is useful for debugging at runtime. The 2nd form requires some extra steps to figure out what kind of object you have.

I know that I could write a descriptive toString function or call the toSource method on the constructor to get some more information, but I want the simplest way possible.

Is there a way to do this? Suggestions?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T10:11:11+00:00Added an answer on May 12, 2026 at 10:11 am

    Well that happens because you are using an anonymous function.

    You can specify names of anonymous functions (yes, it sounds odd), you could:

    var MyJSLib = {
     Person : function Person (name) {
       this.name = name;
     }
    }
    var john2 = new MyJSLib.Person('John');
    console.log(john2.constructor);
    

    Anonymous functions can be named but those names are only visible
    within the functions themselves, and since you use the new operator, the constructor property will be set, and you will be able to see the name.

    You could also compare the constructor reference using or not a name for the function:

    console.log(john2.constructor === MyJSLib.Person); // true
    
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