Question

For example:

<doc>
    <elem attr="firstLine &x0a; secondLine"/>
    <elem attr="1stLine"/>
</doc>

The need is to get the first line, when there are many

From the example above, we want to get { ‘firstLine’, ‘1stLine’}

Thanks in advance

Answer 1

Use:

substring-before(/*/elem[1]/@attr, '
')

Here is an XSLT – based verification:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="/">
     <xsl:copy-of select="substring-before(/*/elem[1]/@attr, '&#x0A;')"/>
 </xsl:template>
</xsl:stylesheet>

when this transformation is applied on the provided XML document (corrected to be well-formed !!!):

<doc>
    <elem attr="firstLine &#x0a; secondLine"/>
    <elem attr="1stLine"/>
</doc>

it evaluates the XPath expression and outputs the result of this evaluation:

firstLine