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Home/ Questions/Q 8473279
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T17:18:23+00:00 2026-06-10T17:18:23+00:00

For example.go, I have package main import html/template import net/http func handler(w http.ResponseWriter, r

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For example.go, I have

package main

import "html/template"
import "net/http"

func handler(w http.ResponseWriter, r *http.Request) {
    t, _ := template.ParseFiles("header.html", "footer.html")
    t.Execute(w, map[string] string {"Title": "My title", "Body": "Hi this is my body"})
}

func main() {
    http.HandleFunc("/", handler)
    http.ListenAndServe(":8080", nil)
}

In header.html:

Title is {{.Title}}

In footer.html:

Body is {{.Body}}

When going to http://localhost:8080/, I only see “Title is My title”, and not the second file, footer.html. How can I load multiple files with template.ParseFiles? What’s the most efficient way to do this?

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-10T17:18:25+00:00Added an answer on June 10, 2026 at 5:18 pm

    Only the first file is used as the main template. The other template files need to be included from the first like so:

    Title is {{.Title}}
    {{template "footer.html" .}}
    

    The dot after "footer.html" passes the data from Execute through to the footer template — the value passed becomes . in the included template.

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