Question

For example I am looking for a way to search every spot in a list to see where an object is located. Some example psuedocode could go:

for every column in current row:
  if column is the first one:
                  do this
  if column in the last one:
                  do that
  else:
     find the previous row and columns place

Basically I am at a standstill so any insight would be helpful thanks

EDIT Sample Code:

for row in range(0,h+1):
      newrow=[]
      if row==0:
           newrow=[1]
      elif row==1:
           newrow=[1,1]
      else:
          for column,x in enumerate(row):
              if column==0:
                  newrow.append(1)
              elif column==len(row)-1:
                  newrow.append(1)
              else:
                  newrow.append(2)

Answer 1

Are you looking for list.index?

l = ['foo', 'bar', 'baz']
i = l.index('bar')
# i is 1, because l[1] == 'bar'

If you need special handling based on whether it’s the first or last item:

# using i from above
if i == 0:
    # it's the first item
elif i == len(l) - 1:
    # it's the last item
else:
    # it's neither first nor last

Or if you need to process all items anyway, consider using enumerate to keep track of indices throughout the loop:

for i, x in enumerate(mylist):
    if i == 0:
        # x is the first item
    elif i == len(mylist)-1:
        # x is the last item
    else:
        # x is in the middle