Question

For Example, i Have 3 lists

list1=['Oh','My','god','I','A','List!']

list2=['Oh','What','You','Dramatic?']

Keyword=['I','Dunno','What','You','Talking','About','DOT']

EDIT

I Want to compare keywords with list 1 and 2 separately. so it would become:

EDIT

common=['What','I','You']

What if i had more than 10 lists? <– optional question.

Answer 1

Since your comment indicates that you want items that exist in both Keyword and either list1 or list2, you probably don’t want an intersection of all three. Instead you should get the union of list1 and list2, and then get the intersection of that result and Keyword.

Something like the following should give you what you want:

common = list((set(list1) | set(list2)) & set(Keyword))

Or an alternative approach that is more extensible (thanks to Karl for the shortened version):

lists = [list1, list2, list3, list4, list5, list6, list7, list8, list9, list10]
common = list(set().union(*lists).intersection(Keyword))