Question

For example I have a website that points to a page like this:

http://www.mysite.com/folder/file

How can I get determine /folder so that I can go further an quote an if statement like

if /folder then echo something

Why do I need this?

I am trying to tell facebook which image to pick from a page. Actually I have a pretty simple page structure and the image that facebook should take is always at first but somehow it does choose another one from time to time. I guess because the other images are loaded faster. And the old way to rel=”img_src” doesn’t seem to work anymore as that I could just add it to the wanted image.

So well of course I use the open graph protocol to tell facebook which Image it should use.

I am working with a cms were I can output the path of the image depending on the id the image has. I have two different id’s for the different kind of pages living in two different folders.

This leads to:

if index --> echo meta og for index img
else if /folderone (with id1) --> echo meta og for id1
else if /foldertwo (with id2) --> echo meta og for id2

This is why I need to know the foldername.

Now with the answer I have following setup, just that you know:

<?php $folder = dirname($_SERVER['SCRIPT_NAME']); ?>

<?php if (dirname($_SERVER['SCRIPT_NAME']) == "/") echo "<meta property='og:image' content='http://www.mysite.com/img/img.jpg'/>" ;?>
<?php if (dirname($_SERVER['SCRIPT_NAME']) == "/folderOne") echo "<meta property='og:image' content='http://www.mysite.com/img/{$img_id1}'/> " ;?>
<?php if (dirname($_SERVER['SCRIPT_NAME']) == "/folderTwo") echo "<meta property='og:image' content='http://www.mysite.com/img/{$img_id2}'/> " ;?>

Answer 1

$script = $_SERVER['SCRIPT_NAME'];
echo dirname($script);