Question

For example I have:

char buff[1000];

I want to search if the string “hassasin” is in that char array. Here is what I have tried.

char word[8] = "hassasin";
char Buffer[1000]=sdfhksfhkasd/./.fjka(hassasin)hdkjfakjsdfhkksjdfhkjh....etc 
int k=0;
int t=0; 
int len=0; 
int sor=0; 
for (k=0; k<1000; k++){ 
    for (t=0; t<8; t++){ 
        if (Buffer[k]==word[t]) len++; 
        if (len==8) "it founds 0.9.1" 
    } 
}

Answer 1

if the chararray contains stringend or do not end with \0 you can use these code, because strstr will brake on these ones:

#include <stdio.h>
int main()
{
    char c_to_search[5] = "asdf";

    char text[68] = "hello my name is \0 there is some other string behind it \n\0 asdf";

    int pos_search = 0;
    int pos_text = 0;
    int len_search = 4;
    int len_text = 67;
    for (pos_text = 0; pos_text < len_text - len_search;++pos_text)
    {
        if(text[pos_text] == c_to_search[pos_search])
        {
            ++pos_search;
            if(pos_search == len_search)
            {
                // match
                printf("match from %d to %d\n",pos_text-len_search,pos_text);
                return;
            }
        }
        else
        {
           pos_text -=pos_search;
           pos_search = 0;
        }
    }
    // no match
    printf("no match\n");
   return 0;
}

http://ideone.com/2In3mr