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Home/ Questions/Q 7840029
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T15:38:20+00:00 2026-06-02T15:38:20+00:00

For example, I have something like: <div id=buttons> <button class=button>Click</button> </div> <script> $(document).ready(function() {

  • 0

For example, I have something like:

<div id="buttons">
    <button class="button">Click</button>
</div>

<script>
    $(document).ready(function() {
        $('.button').click(function() {
            $('#buttons').append('<button class="button">Click</button>');
        });
    });
</script>

When I press “Click” button, the script will create a new button with the same class “button”.
When I press this new button — nothing happens.

I understand why, but I don’t know how to avoid this.
I want my script “see” just created button.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T15:38:21+00:00Added an answer on June 2, 2026 at 3:38 pm

    Use on to bind to delegated events

    $("#buttons").on("click", ".button", function () {
       $('#buttons').append('<button class="button">Click</button>');    
    });
    

    Example: http://jsfiddle.net/66H8W/

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