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Home/ Questions/Q 8653953
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T14:39:59+00:00 2026-06-12T14:39:59+00:00

For example, if I had two lists, I’d do: foreach (Item item1 in lists[0])

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For example, if I had two lists, I’d do:

foreach (Item item1 in lists[0])
  foreach (Item item2 in lists[1])
    // Do something with item1 and item2

Or if I had three, I’d do

foreach (Item item1 in lists[0])
  foreach (Item item2 in lists[1])
    foreach (Item item3 in lists[2])
      // Do something with item1, item2, and item3

but if I don’t know at compile time how many lists are in the lists collection, how can I easily iterate over every permutation?

A C# solution is ideal, but a solution in any language that demonstrates a suitable algorithm would be handy.

A good 2-dimensional example would be a list of columns and a list of rows on a spreadsheet, where I need to do processing on each cell. It’s an n-dimensional problem, however.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T14:40:00+00:00Added an answer on June 12, 2026 at 2:40 pm

    There is a wonderful article on the subject by Eric Lippert.

    I highly suggest reading the article, as it describes the process by which you can arrive at the result, but at the end the resulting code is short and sweet:

    (Copied verbatim from the link)

    static IEnumerable<IEnumerable<T>> CartesianProduct<T>(this IEnumerable<IEnumerable<T>> sequences) 
    { 
      IEnumerable<IEnumerable<T>> emptyProduct = new[] { Enumerable.Empty<T>() }; 
      return sequences.Aggregate( 
        emptyProduct, 
        (accumulator, sequence) => 
          from accseq in accumulator 
          from item in sequence 
          select accseq.Concat(new[] {item})); 
    }
    
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