Question

For example if I input the year – 2012 and the day 72, it should return Tuesday.The following code will return proper day of the week, but requires month as an input. How could I do this without the month argument, since I am not requiring a user to type in a month?

days = {0:'Monday', 1:'Tuesday', 2:'Wednesday', 3:'Thursday', 4:'Friday', 5:'Saturday', 6:'Sunday'}

userdate = date(year, month, day)
weekday = userdate.weekday()

return days[weekday]

Answer 1

OR:

from datetime import datetime, timedelta

startDate = datetime(your_year, 1, 1)
endDate = (startDate + timedelta(days=days_from_the_begining)).weekday()

E.g:

from datetime import datetime, timedelta

def get_weekday(year, dayOfTheYear):
    days = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']

    userWeekDay = (datetime(year, 1, 1) + timedelta(days=dayOfTheYear)).weekday()
    return days[userWeekDay]