Question

For example if you have an integer:

int i = 9;

How can it do that? I mean the full syntax is:

int i = new Integer(9);

How does it skip the whole new Integer() part and still work?

Thanks.

Answer 1

new Integer() is not a primitive; it’s a boxed primitive.
Actual primitives (int, etc) are not objects and cannot be instantiated.

Note that you can also write Integer x = 9, and the Java compiler will implicitly insert new Integer().
This is called auto-boxing.