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Asked: 2026-05-10T15:13:13+00:00

For example: me$ FOO=BAR * BAR me$ echo $FOO BAR file1 file2 file3 file4

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For example:

me$ FOO='BAR * BAR' me$ echo $FOO BAR file1 file2 file3 file4 BAR

and using the \ escape character:

me$ FOO='BAR \* BAR' me$ echo $FOO BAR \* BAR

I’m obviously doing something stupid.

How do I get the output BAR * BAR?

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1 Answer

  1. Quoting when setting $FOO is not enough. You need to quote the variable reference as well:

    me$ FOO='BAR * BAR' me$ echo '$FOO' BAR * BAR
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