Question

For example, my XML code is:

<part> 
      <name>qwe</name>
      <ir>
          <d>yes</d>
          <scalar>
              <left>31</left>
              <right>0</right>
          </scalar>
      </ir>
</part>
<part> 
      <name>qaz</name>
      <ir>
          <d>yes</d>
          <scalar>
              <left>1</left>
              <right>0</right>
          </scalar>
      </ir>
</part>
<part>
      <name>asd</name>
      <ir>
          <d>yes</d>
          <drive>
              <default>1</default>
          </drive>
      </ir>
</part>
<part> 
      <name>zxc</name>
      <ir>
          <d>no</d>
          <scalar>
              <left>3</left>
              <right>0</right>
          </scalar>
          <drive>
              <default>0</default>
          </drive>
      </ir>
</part>

I want to extract all the names which don’t have a node default, i.e. the output should be qwe, qaz in this example. You have to check the value of default value if it is 0 or 1 and print that asd has default 0 and zzxc has default 1. if it doesn’t exist print that qwe has no default and qaz has no default value.

Answer 1

If the default is always in ir/drive, you can just use the following XPath expression:

//part[not(ir/drive/default)]/name/text()