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Home/ Questions/Q 6634021
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T22:52:52+00:00 2026-05-25T22:52:52+00:00

For example, PHP code: $test = hello; ${$test} = $test; echo $hello; // return

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For example, PHP code:

$test = "hello";
${$test} = $test;
echo $hello; // return hello

How to do this in C#? Thanks in advance.


UPD: Dynamic variable in C#? – here is an answer.

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  1. Editorial Team
    Editorial Team
    2026-05-25T22:52:53+00:00Added an answer on May 25, 2026 at 10:52 pm

    This isn’t supported in C#. You could use an ExpandoObject and set a member on it, but it’s not quite the same as the PHP code. You’ll still need to refer to the ExpandoObject by a variable name.

    dynamic myObject = new ExpandoObject();
    string test = "Hello";
    ((IDictionary<string, object>)myObject).Add(test, test);
    Console.WriteLine(myObject.Hello);
    

    Nonetheless, this doesn’t help with code clarity. If all you want to do is map a name to a value you can use a Dictionary, which is really what ExpandoObject uses internally, as demonstrated by the cast in the code above.

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