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Home/ Questions/Q 259219
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T22:14:44+00:00 2026-05-11T22:14:44+00:00

for example qa_sharutils-2009-04-22-15-20-39 , want chop last 20 bytes, and get ‘ qa_sharutils ‘.

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for example qa_sharutils-2009-04-22-15-20-39, want chop last 20 bytes, and get ‘qa_sharutils‘.

I know how to do it in sed, but why $A=${A/.\{20\}$/} does not work?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-11T22:14:44+00:00Added an answer on May 11, 2026 at 10:14 pm

    If your string is stored in a variable called $str, then this will get you give you the substring without the last 20 digits in bash

    ${str:0:${#str} - 20}
    

    basically, string slicing can be done using

    ${[variableName]:[startIndex]:[length]}
    

    and the length of a string is

    ${#[variableName]}
    

    EDIT:
    solution using sed that works on files:

    sed 's/.\{20\}$//' < inputFile
    
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