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Home/ Questions/Q 1105125
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:34:59+00:00 2026-05-17T01:34:59+00:00

For example: SELECT COUNT(ID) FROM My_Table WHERE ID < (SELECT ID FROM My_Table WHERE

  • 0

For example:

SELECT COUNT(ID) FROM My_Table
WHERE ID < 

(SELECT ID FROM My_Table
WHERE ID LIKE '%4'
ORDER BY ID LIMIT 1)    

My_Table:

  X          ID    Y     
------------------------
|      |     A1  |     |
------------------------
|      |     B2  |     |
------------------------
|      |     C3  |     |
------------------------ -----Page 1
|      |     D3  |     |
------------------------
|      |     E3  |     |
------------------------
|      |     F5  |     |
------------------------ -----Page 2
|      |     G5  |     |
------------------------
|      |     F6  |     |
------------------------
|      |     G7  |     | -----Page 3

There is no data ending in 4 but there still are 5 rows that end in something less than “%4“.

However, in this case were there is no match, so SQLite only returns 0

I get it is not there but how do I change this behavior to still return number of rows before it, as if it was there?

Any suggestions?

Thank You.

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  1. Editorial Team
    Editorial Team
    2026-05-17T01:35:00+00:00Added an answer on May 17, 2026 at 1:35 am
    SELECT COUNT(ID) FROM My_Table
    WHERE ID < (SELECT ID FROM My_Table
      WHERE SUBSTRING(ID, 2) >= 4
    ORDER BY ID LIMIT 1)   
    
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