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Home/ Questions/Q 4040600
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T12:46:23+00:00 2026-05-20T12:46:23+00:00

For example suppose I have the following join join on p.match_id = o.match_id Could

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For example suppose I have the following join

join on p.match_id = o.match_id

Could I specify instead that if p.match_id is even then

join on p.match_id = o.match_id - 1

But if it is odd then

join on p.match_id = o.match_id + 1

I have sequential match_id such that consecutive values represent a single match. Therefore to work out an opponent for a given match_id I need the above

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T12:46:23+00:00Added an answer on May 20, 2026 at 12:46 pm

    Edited so it doesn’t use CASE. The subquery returns a table with one field: matchid (equals match_id+1 when match_id is even and match_id-1 when match_id is odd).

    SELECT matchid
      FROM ( SELECT match_id + 1 - 2*(match_id % 2)
                    AS matchid
               FROM p
           ) AS p2
      JOIN o
        ON p2.matchid = o.match_id
    ;
    

    Since you mention that you are using one table and 2 sequentials ids for one pair of opponents, you can also use the following as a subquery or a view:

    SELECT match_id
         , ((match_id + 1) DIV 2) AS pair
      FROM p
    ;
    

    It will give you a table that you can then collerate to itself:

    | match_id | pair |
    |     1    |   1  |
    |     2    |   1  |
    |     3    |   2  |
    |     4    |   2  |
    |     5    |   3  |
    |     6    |   3  |
    
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