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Home/ Questions/Q 820833
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T02:32:31+00:00 2026-05-15T02:32:31+00:00

For example, take a look at this code (from tspl4): (define proc1 (lambda (x

  • 0

For example, take a look at this code (from tspl4):

(define proc1
  (lambda (x y)
    (proc2 y x)))

If I run this as my program in scheme…

#!r6rs
(import (rnrs))

(define proc1
  (lambda (x y)
    (proc2 y x)))

I get this error:

expand: unbound identifier in module in: proc2

…This code works fine though:

#!r6rs
(import (rnrs))

(define proc2
  +)

(define proc1
  (lambda (x y)
    (proc2 y x)))

(display (proc1 2 3)) ;output: 5
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T02:32:32+00:00Added an answer on May 15, 2026 at 2:32 am

    They all have to be defined in the same module (= “library” in r6rs lingo). But you can define them in any order you want — for example, in your last snip you can swap the two definitions and it will work fine. But note that you cannot put the definitions after the display line — this is an expression that uses their value, so if you move the function definitions after it, you’ll get a runtime error. (Note the fact that it’s a runtime error rather than a compile-time one.)

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