Question

For example:

//test.php
#! /usr/local/php/bin/php
<?php
exec('nohup ./loop.php > loop.out');
echo 'I am a superman!';

//loop.php
#! /usr/local/php/bin/php
<?php
$count = 0;
while (true) {
    echo "Loop count:{$count}\n";
    $count++;
}

When I run ./test.php I can not get the output ‘I am a superman!’, as you know loop.php is an endless loop, test.php is interrupted by loop.php, so how can I get the output? Any help is appreciated.

Answer 1

There is a bunch of ways you can achieve this:

Running background process using &:

exec('nohup ./loop.php > loop.out 2>&1 &');

Using pcntl_fork and running your process from child:

 $pid = pcntl_fork();
 switch ($pid){
   case -1:
     die('Fork failed');
     break;
   case 0:
     exec('nohup ./loop.php > loop.out');
     exit();
   default:
     break;
 }
 echo "I'm not really a superman, just a parent process';

There is more ways to do this, just lurk into PHP documentation and questions in php here…