Question

for i = 1:n
        ymin = realmax;
        ymax = 0;
        for j = 1:4 % each perceptron
            for k = 1:40
                yval = waves0(k,j,i);
                if(yval > ymax) ymax = yval;
                if(yval < ymin) ymin = yval;
            end
        end
end

I’m trying to find the min and max value, yet when I run the function I get:

parse error near line 20 of file /Volumes/FDISK/mlr/YvalDistance.m

  syntax error



parse error near line 20 of file /Volumes/FDISK/mlr/YvalDistance.m

  syntax error



parse error near line 20 of file /Volumes/FDISK/mlr/YvalDistance.m

  syntax error



parse error near line 20 of file /Volumes/FDISK/mlr/YvalDistance.m

  syntax error

Line 20 is the last line of the function, and is empty.
If I comment if(yval < ymin) ymin = yval; I don’t get the parse error anymore. What’s up?

octave:39> version
ans = 3.2.4

Answer 1

Why not get rid of your syntax error and speed up your code with:

yvals = zeros(1,4*40);
for j = 1:4
    for k = 1:40
        yvals((j*4)+k) = waves0(k,j,i);
    end
end
ymax = max(yvals);
ymin = min(yvals);