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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:10:29+00:00 2026-05-13T21:10:29+00:00

For instance, if I have got a vector describing a rectangle xy=[165 88; 401

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For instance, if I have got a vector describing a rectangle

xy=[165  88; 
    401  88; 
    401 278; 
    165 278];

on an image.

How can I obtain the following vector

[165  88; % increase X -     hold y
 166  88; 
 167  88;
   ...  ;
 399  88;
 400  88;
 401  88; % hold     x - increase y
 401  89;
 401  90;
 401  91;
   ...  ;
 401 276;
 401 277;
 401 278; % decrease X -     hold y
 400 278;
 399 278;
 398 278;
   ...  ;
 167 278;
 166 278;
 165 278; % hold     x - decrease y
 165 277;
 165 276;
   ...  ;
 165  87];

using a MATLAB inbuilt function or do I need to write it using FOR LOOPS?

The algorithm must work for a generic vector with n-points and xy coordinates.

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:10:29+00:00Added an answer on May 13, 2026 at 9:10 pm

    If you have the image processing toolbox, you can do this by creating an image of the polygon followed by finding the contour:

    xy=[165 88; 401 88; 401 278; 165 278];
    %# create the image - check the help for impolygon for how to make sure that
    %# your line is inside the pixel
    img = poly2mask(xy(:,1),xy(:,2),max(xy(:,1))+3,max(xy(:,2))+3);
    figure,imshow(img) %# show the image
    
    %# extract the perimeter. Note that you have to inverse x and y, and that I had to
    %# add 1 to hit the rectangle - this shows one has to be careful with rectangular 
    %# polygons
    boundary = bwtraceboundary(logical(img),xy(1,[2,1])+1,'n',8,inf,'clockwise');
    
    %# overlay extracted boundary
    hold on, plot(boundary(:,2),boundary(:,1),'.r')
    

    Edited to show how to use bwtraceboundary and to warn of pixel offset with rectangles.

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