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Home/ Questions/Q 7622943
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T04:34:54+00:00 2026-05-31T04:34:54+00:00

For my actual web-project, I made a tagcloud. When I click on a tag,

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For my actual web-project, I made a tagcloud. When I click on a tag, it should be passed to the page showRecipesFromTags.php.

<form name="tagform" id="tagform" method="get" action="/showRecipesFromTags.php">
<?php
include('php/getRandomTags.php');
$tagsarr = json_decode($return4634, true);

foreach ($tagsarr['Data']['Tag'] as $key => $tag11) {   
echo '<a id="seastags" href="#" onclick="document.tagform.submit()"><font size="' . rand(1,4) .'">' . $tag11['Tag_name'] . '</font> <br/></a> ';
}
?>
</form>

It can already go to this page by clicking on the href, but what I need is to pass the id of the clicked tag. The name of the tag is called Tag_name. The name is shown but I don´t know how the pass the id to the next site. The id is in my JSON array and is called Tag_id.

How can I manage this?

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  1. Editorial Team
    Editorial Team
    2026-05-31T04:34:55+00:00Added an answer on May 31, 2026 at 4:34 am

    Why do you even need a form? Just use plain links.
    Try using this in the foreach loop:

    echo '<a id="seastags" href="/showRecipesFromTags.php?tagId=' .$tag11['Tag_id'] . '"><font size="' . rand(1,4) .'">' . $tag11['Tag_name'] . '</font> <br/></a> ';

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