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Home/ Questions/Q 990317
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:55:50+00:00 2026-05-16T05:55:50+00:00

For my first question here I would like to ask you how you’d do

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For my first question here I would like to ask you how you’d do the following in Ruby.

I have a hash with the following aspect

variables["foo"] = [1,2,3]
variables["bar"] = [4,5,6,7]
variables[...] = ...

Update: this hash will have an arbitrary number of key => values pairs.

So it represents parameters and their possible values. I would like to “generate” now an Array containing hashes whose key=>value pairs represent each possible combination of the variables. In the case of the example above, I would have an array of 12 (=3×4) hashes like that

[ hash1, hash2, ..., hash16]

where hashi would be

 hash1["foo"] = 1
 hash1["bar"] = 4
 hash2["foo"] = 1
 hash2["bar"] = 5
 hash3["foo"] = 1
 hash3["bar"] = 6
 hash4["foo"] = 1
 hash4["bar"] = 7
 hash5["foo"] = 2
 hash5["bar"] = 4
 hash6["foo"] = 3
 hash6["bar"] = 4
 ...
 hash16["foo"] = 3
 hash16["bar"] = 7

I have a few ideas but all of them are quite complicated nested loops …

Thanks a lot !

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  1. Editorial Team
    Editorial Team
    2026-05-16T05:55:52+00:00Added an answer on May 16, 2026 at 5:55 am
    vars = {foo: [1, 2, 3], bar: [4, 5, 6, 7]}
    
    (v = vars.map {|k, v| ([k] * v.length).zip(v) }).first.product(*v.drop(1)).
    map {|args| args.reduce({}) {|h, (k, v)| h.tap {|h| h[k] = v }}}
    # => [{:foo=>1, :bar=>4},
    # =>  {:foo=>1, :bar=>5},
    # =>  {:foo=>1, :bar=>6},
    # =>  {:foo=>1, :bar=>7},
    # =>  {:foo=>2, :bar=>4},
    # =>  {:foo=>2, :bar=>5},
    # =>  {:foo=>2, :bar=>6},
    # =>  {:foo=>2, :bar=>7},
    # =>  {:foo=>3, :bar=>4},
    # =>  {:foo=>3, :bar=>5},
    # =>  {:foo=>3, :bar=>6},
    # =>  {:foo=>3, :bar=>7}]
    

    This works with arbitrary many entries and arbitrary keys.

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