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Editorial Team
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Asked: 2026-05-13T18:16:46+00:00

for now i could use clazz.getClassLoader().getResource(class.getName()), then i substring the URL to get the

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for now i could use clazz.getClassLoader().getResource(class.getName()), then i substring the URL to get the jar file’s location, but i really want to know if there is any better way to do it.

is there any API for this? thank you.

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1 Answer

  1. Editorial Team

    If your class is called Foo

    URL classLocation = Foo.class.getProtectionDomain().getCodeSource().getLocation()

    classLocation will contain the URL where the class was loaded from. Either a folder for a stand alone class or a jar/zip.

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