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Home/ Questions/Q 9256617
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T11:59:14+00:00 2026-06-18T11:59:14+00:00

For scaling/failover mongodb uses a replica set where there is a primary and one

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For scaling/failover mongodb uses a “replica set” where there is a primary and one or more secondary servers. Primary is used for writes. Secondaries are used for reads. This is pretty much master slave pattern used in SQL programming.
If the primary goes down a secondary in the cluster of secondaries takes its place.
So the issue of horizontally scaling and failover is taken care of. However, this is not a solution which allows for sharding it seems. A true shard holds only a portion of the entire data, so if the secondary in a replica set is shard how can it qualify as primary when it doesn’t have all of the data needed to service the requests ?

Wouldn’t we have to have a replica set for each one of the shards?

This obviously a beginner question so a link that visually or otherwise illustrates how this is done would be helpful.

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  1. Editorial Team
    Editorial Team
    2026-06-18T11:59:15+00:00Added an answer on June 18, 2026 at 11:59 am

    Your assumption is correct, each shard contains a separate replica set. When a write request comes in, MongoS finds the right shard for it based on the shard key, and the data is written to the Primary of the replica set contained in that shard. This results in write scaling, as a (well chosen) shard key should distribute writes over all your shards.

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