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Home/ Questions/Q 6671849
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T03:26:22+00:00 2026-05-26T03:26:22+00:00

For some reason ajax is not sending data. On the PHP I have this

  • 0

For some reason ajax is not sending data.

On the PHP I have this code:

if (isset($_POST['submit'])) { 
    echo "submit";
} else {
    echo "not submit";
}

And I get not submit.
This is JS code:

$(function () {
    $('#submit').click(function () {
        var length = $('#number').val();
        var small = $('#small').val();
        var big = $('#big').val();
        var number = $('#numero').val();
        var special = $('#special').val();
        var submit = 'submit';
        var url = 'public/php/codegenerator.php';
        var data = "length=" + length + "&small=" + small + "&big=" + big +
                   "&number=" + number + "&special=" + special + "&submit=" + submit;

        $.ajax({
            type: "POST",
            url: url,
            data: data,
            success: function () {
                $('#code').load(url, function () {
                    $(this).fadeIn(1000)
                });
            }
        });
        return false;
    });
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T03:26:22+00:00Added an answer on May 26, 2026 at 3:26 am

    You can try this approach

    $(function(){
        $('#submit').click(function(){
            //YOUR CODE
    
           var param = {
                length:length,
                small:small,
                big:big,
                number:number,
                special:special,
                submit:submit
            }
    
             $.ajax({
                type: "POST",
                url: url,
                data: param,   
    
                //EDITED LINE     
                success: function (data) {
                    $('#code').hide().html(data).fadeIn(1000);
                }               
            });       
            return false;
        });               
    });
    

    // REVISED ANSWER

    // IN YOUR PHP FILE

    if (isset ($_POST['submit'])) { 
        echo json_encode(array('result'=>"submit"));
    }
    else {
        echo json_encode(array('result'=>"not submit"));
    }
    

    //IN YOUR JQUERY CODE

    $.ajax({
        type: "post",
        url: url,
        data: param, 
        dataType:'json';  
    
        //EDITED LINE     
        success: function (data) {
            // alert(data.result);
            $('#code').hide().html(data.result).fadeIn(1000);
        }               
    });
    
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