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Asked: 2026-05-23T10:17:19+00:00

For some reason Decimal object looses precision when multiplied. There is no reason to

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For some reason Decimal object looses precision when multiplied. There is no reason to happen so. Please check the testcase and enlighten me.

from decimal import *
getcontext().prec = 11

a = Decimal('5085.28725881485')
b = 1

print getcontext()
print 'a     = '+str(a)
print 'b     = '+str(b)
print 'a * b = '+str(a * b)

And the output:

Context(prec=11, rounding=ROUND_HALF_EVEN, Emin=-999999999, Emax=999999999, capitals=1, flags=[], traps=[DivisionByZero, InvalidOperation, Overflow])
a     = 5085.28725881485
b     = 1
a * b = 5085.2872588

Not sure if this is relevant, but python2.6 used.

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1 Answer

  1. Editorial Team

    The precision you specify in the context (11 places) is only applied when performing calculations, not when creating decimal.Decimal objects — and the result, 5085.2872588 does indeed obey that limit. Using 1 as the multiplier does not change the rules with regards to precision; the result of arithmetic operations always considers the precision.

    If you were instead looking for decimal.Decimal to return a number rounded to a particular number of places, the create_decimal method of the context object will do that for you.

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