Question

For some reason, I am unable to print the entire linked list. Where could I be going wrong?
Please help. Thanks in advance.

The basic structure of the list.

struct node
{
    int num;
    struct node *next;
};

typedef struct node *list;

Main function.

int main()
{
    int i, j, k, l;
    list head = NULL, start = NULL, temp, p;

    printf("Enter the number of nodes in the list: ");
    scanf("%d", &k);

Formation of the linked list.

    for(i=0;i<k;i++)
    {
        if (i==0)
        {
            start = (list) malloc(sizeof(struct node));
            start->num = i;
            head = start;
            head->next = NULL;
        }
        else
        {   
            temp = (list) malloc(sizeof(struct node));
            temp->num = i;
            head->next = temp;
            head->next = NULL;
        }
    }   

Printing the linked list.

    p = start;
    while(p != NULL)
    {
        printf("%d", p->num);
        p = p->next;
    }
    return 0;
}

Answer 1

Aren’t you missing here something:

head->next = temp;
head->next = NULL;

You are overriding your next head with NULL. You should have your head at first point to temp.

head->next = temp;   // (4) see my comment on this post for 
head = temp;         // (5) the meaning of the number
head->next = NULL;   // (6)

Edit: By the way, you should rename head to current/last or something like that. Else, one could easily swap the meaning of head and start.