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Home/ Questions/Q 6593149
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T17:38:43+00:00 2026-05-25T17:38:43+00:00

For some reason, the following code does not work: char cValue = ‘8’; int

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For some reason, the following code does not work:

char cValue = '8';
int digits = (int)cValue;

It keeps giving some value of 5 or 7, or something along those lines.

I’m just curious why – I’m using Character.getNumericValue(cValue); instead.

Why does this happen?

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  1. Editorial Team
    Editorial Team
    2026-05-25T17:38:44+00:00Added an answer on May 25, 2026 at 5:38 pm

    You can typecast char to int, and in fact you are. The binary representation of the character ‘8’ is actually 56 (decimal). See any ASCII chart for the conversions. What you’re looking for is parsing, not casting. getNumericValue() parses the char and gives you its numeric equivalent. Casting the char simply changes the type and leaves the pattern of bits the same. The bits are then interpreted according to the type of the variable they’re associated with.

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