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Home/ Questions/Q 6214533
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T06:53:41+00:00 2026-05-24T06:53:41+00:00

For some reason, when I do the code… def encode(): result2 = [] print

  • 0

For some reason, when I do the code…

def encode():
    result2 = []
    print result  
    for x in result:  
        result2 += str(x)  
    print result2

I get…

[123, 456, 789]
['1', '2', '3', '4', '5', '6', '7', '8', '9']

How do I get it to return ['123', '456', '789']?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-24T06:53:41+00:00Added an answer on May 24, 2026 at 6:53 am

    How about:

    result2 = [str(x) for x in result]
    

    The reason you are getting what you are getting is the += is doing list concatenation. Since str(123) is '123', which can be seen as ['1', '2', '3'], when you concatenate that to the empty list you get ['1', '2', '3'] (same thing for the other values).

    For it to work doing it your way, you’d need:

    result2.append(str(x)) # instead of result2 += str(x)
    
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