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Home/ Questions/Q 7794775
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T22:52:25+00:00 2026-06-01T22:52:25+00:00

for (Something something : setOfSomething) // OK for (Something const& something : setOfSomething) //

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for (Something something : setOfSomething)          // OK
for (Something const& something : setOfSomething)   // OK
for (Something& something : setOfSomething)         // ERROR

error: invalid initialization of reference of type 'Something&'
from expression of type 'const Something'

Since when does iterator return const Something? It should return either Something& or Something const&. And since range-based ‘for’ loop is interpreted like that, I have no plausible explanation for what’s going on.

Edit: I’m talking about unordered_set rather than set, sorry about this confusion.

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  1. Editorial Team
    Editorial Team
    2026-06-01T22:52:26+00:00Added an answer on June 1, 2026 at 10:52 pm

    You can’t mutate the members of a set because that could violate the set invariants. So the compiler restricts you to getting const references or copies back out.

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