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Home/ Questions/Q 8963815
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T16:26:31+00:00 2026-06-15T16:26:31+00:00

For the following code: def isString(x): if type(x)==str: return True return False When I

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For the following code:

def isString(x):
  if type(x)==str:
    return True
  return False

When I input a string into the parameter, after returning True, why wouldn’t it also then return False? I’m new to Python and I’m confused because I assumed it would then return False because it is out of the for loop, however it doesn’t.

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  1. Editorial Team
    Editorial Team
    2026-06-15T16:26:32+00:00Added an answer on June 15, 2026 at 4:26 pm

    The answer is the same for any language. The return statement means return from the function, giving an optional value back. It can only return once. In this case it returns out of the conditional statement.

    BTW, for type checking like that use the is operator.

    if type(x) is str:
        return True
    

    But, in fact, the real recommended way to do string type checking is:

    if isinstance(x, str):
        return True
    

    However, since it’s so short you don’t really need t write your function for this at all (except for learning purposes). Just use isinstance(x, str) where you would have otherwise wrote isString(x).

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